- Report: Eastern conference executive says Andre Drummond ‘definitely out of Cleveland’
- Former NBA executive discloses how much Cavs would likely pay Jarrett Allen in long-term deal
- Andre Drummond has hilarious reaction to finding out Cavs traded for another center in Jarrett Allen
- Report: Cavs waive 2 players in aftermath of blockbuster James Harden trade
- Report: Cavs acquire Jarrett Allen and Taurean Prince in blockbuster James Harden deal
- Report: Cavs helping Kevin Porter Jr. ‘get his life together before putting him on the court’
- Report: Cavs reveal MRI results of Collin Sexton’s latest injury
- Report: Cavs considered adding Jeremy Lin before signing Yogi Ferrell
- Kevin Porter Jr. highlights relationship with Carmelo Anthony as he remains away from Cavs
- Report: Steve Nash continues to have no update on Kyrie Irving’s mysterious absence from Nets
Video: Byron Scott Takes Stand on LeBron’s Rank in Today’s NBA
- Updated: April 19, 2017
The NBA has experienced a superstar revival over the past few months. With MVP candidates James Harden and Russell Westbrook putting up historic numbers and San Antonio Spurs star Kawhi Leonard growing elite offensively, Cleveland Cavaliers forward LeBron James has seemingly flown under the radar.
However, according to former Los Angeles Lakers head coach Byron Scott, James is without a doubt still the best player in today’s game.
"[LeBron James] is still the best player in this league." — Byron Scott
RT if you agree with Byron pic.twitter.com/RluSIUwT0E
— UNDISPUTED (@undisputed) April 18, 2017
While much of the debate will depend on how far the former MVP takes the Cavs this postseason, James has still done wonders this past regular season. The 32-year-old finished the regular season averaging 26.4 points in addition to a career-high 8.7 assists and 8.6 rebounds a game.
James will continue his quest for a fourth championship when the Cavs take on the Indiana Pacers on Thursday at 7 p.m. E/T at Bankers Life Fieldhouse for Game 3 of the Eastern Conference quarterfinals.